# One Solution Rule

If we replace these two solutions with the original equation, the results are positive answers and can never be equally negative. It`s absurd; Therefore, there is no solution to the equation. Therefore, the given linear equation has a null solution or the number of solutions is zero. For rational equations, we must first note the interval which is all real numbers except and. In other words, it is the values of , that cause the equation to be undefined. Since is the lowest common denominator of , and , each term can be multiplied by the LCD to cancel the denominators and reduce the equation to. The combination of similar terms ends with us. Dividing the two sides of the equation by the constant gives an answer of. However, this solution is NOT in the field. Therefore, there is no solution because it is an irrelevant answer. Here we will try to find the number of possible solutions of a linear equation. Use the replace method to resolve the solution for the solution set. If a system has at least one solution, it is said to be consistent.

The two equations y = 2 x + 5 and y = 4 x + 3 form a system of equations. The ordered pair which is the solution of the two equations is the solution of the system. If we divide the equation into its positive and negative solutions, we have: * Any method for finding the solution of this system of equations leads to an answer without solution. When solving, we have 7x = 35 or x = 5. The above linear equation is true only if x = 5 and therefore the given linear equation has only one solution, i.e. x = 5. If equation 1 were solved for one variable and then inserted into the second equation, a similar result would be found. This is because these two equations have no solution. Edit both equations as slope sections and graphs for visualization. These lines are parallel; They cannot overlap. When determining the number of solutions in an equation, you must look at constants and coefficients. If a coherent system has an infinite number of solutions, it is dependent.

If you draw the equations, the two equations represent the same line. If a system has no solution, it is said to be inconsistent. The graphs of the lines do not intersect, so the graphs are parallel and there is no solution. Therefore, the given linear equation has only one solution, i.e. x = 80. From the above examples, we can see that the variable x disappears/is eliminated and so we say that the linear equation will have zero or no solution if it cannot be satisfied by any value of the variable or if there is no value of the variable, making the given equation a true statement. If the coefficients are the same on both sides, the sides are not equal, so no solution will occur. A system of two linear equations can have one solution, an infinite number of solutions, or no solution at all. Systems of equations can be classified according to the number of solutions.

From the above examples, we see that the variable x does not disappear after resolution and we say that the linear equation has a solution if it is satisfied by exactly one value of the variable. To get answers/solutions to questions or to learn concepts, join a FREE TRIAL SESSION. Solve the following linear equations and determine whether the given linear equations have one, zero, or infinite solution. If you see this message, it means that we are having trouble loading external resources on our website. The left side does not satisfy the equation because the fraction cannot be divided by zero. The coefficients are the numbers next to the variables. Collect the same conditions from both sides by transferring them, we have. We have -35 = -27, which is a false statement because it cannot be true for any value of the variable x. Example 2: Consider equation 9(x – 1) – 35 = 8x + 37. eTutorWorld offers affordable private lessons over the Internet for K-12 classes, assistance with preparation for standardized tests such as SCAT, CogAT, MAP, SSAT, SAT, ACT, ISEE and AP.

You can schedule private lessons online on your personal hours, all with a money-back guarantee. The first online tutoring session is always FREE, no purchase required, no credit card required. When solving, we have 3x + 27 + 21 x = 24x + 9 or 24 x + 27 = 24x + 9 Khan Academy is a 501(c)(3) non-profit organization. Donate or volunteer today! However, let`s put that answer back into the original equation to see if we`ll get an answer. If you are behind a web filter, make sure that the *.kastatic.org and *.kasandbox.org domains are unlocked.